What are the solutions to the equation (3x-2)(x+4)=0 ?

The solutions to the equation (3x-2)(x+4)=0 are x= 2/3 ,x=-4

Find the zeros of (3x-2)(x+4)=0

The zeros of (3x-2)(x+4)=0 are x= 2/3 ,x=-4

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(3 x - 2) (x + 4) = 0

x = \frac{2}{3}, x = - 4

Decimal Notation

x = 0.66666 \dots, x = - 4

Solution steps

(3 x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x + 4 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 4

- 8 (7 i - 3 i^{2})

\frac{14 !}{10 ! 4 !}

\frac{m ^{2} - 81}{m - 9}

(x - 5) (x + 1) < 0

2^{2} + x^{2} = 3^{2}

What are the solutions to the equation (3x-2)(x+4)=0 ?
The solutions to the equation (3x-2)(x+4)=0 are x= 2/3 ,x=-4
Find the zeros of (3x-2)(x+4)=0
The zeros of (3x-2)(x+4)=0 are x= 2/3 ,x=-4