What are the solutions to the equation 2^2+3^2=x^2 ?

The solutions to the equation 2^2+3^2=x^2 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 2^2+3^2=x^2

The zeros of 2^2+3^2=x^2 are x=sqrt(13),x=-sqrt(13)

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2^{2} + 3^{2} = x^{2}

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

2^{2} + 3^{2} = x^{2}

Switch sides

x^{2} = 2^{2} + 3^{2}

Simplify

2^{2} + 3^{2} : 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

40 + j 20

\frac{6}{- i}

4 x^{2} + 16 (0)^{2} = 64

4 x - 12 = 0

\frac{( 2 a - 2 b ) ^{2}}{a - b}

What are the solutions to the equation 2^2+3^2=x^2 ?
The solutions to the equation 2^2+3^2=x^2 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 2^2+3^2=x^2
The zeros of 2^2+3^2=x^2 are x=sqrt(13),x=-sqrt(13)