What are the solutions to the equation 5x^2-3x+4=0 ?

The solutions to the equation 5x^2-3x+4=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)

Find the zeros of 5x^2-3x+4=0

The zeros of 5x^2-3x+4=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 3 x + 4 = 0

x = \frac{3}{10} + i \frac{71}{10}, x = \frac{3}{10} - i \frac{71}{10}

Solution steps

5 x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 4 : 71 i

x_{1, 2} = \frac{- ( - 3 ) \pm 71 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 71 i}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 71 i}{2 \cdot 5}

x = \frac{- ( - 3 ) + 71 i}{2 \cdot 5} : \frac{3}{10} + i \frac{71}{10}

x = \frac{- ( - 3 ) - 71 i}{2 \cdot 5} : \frac{3}{10} - i \frac{71}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} + i \frac{71}{10}, x = \frac{3}{10} - i \frac{71}{10}

60 w + 5 = 125

3 \cdot \frac{3}{4}

x^{2} - 6 x \geq 16

\frac{12}{5} \cdot \frac{1}{2}

\frac{- 6}{4}

What are the solutions to the equation 5x^2-3x+4=0 ?
The solutions to the equation 5x^2-3x+4=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)
Find the zeros of 5x^2-3x+4=0
The zeros of 5x^2-3x+4=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)