What are the solutions to the equation 2t^2-24t+70=0 ?

The solutions to the equation 2t^2-24t+70=0 are t=7,t=5

Find the zeros of 2t^2-24t+70=0

The zeros of 2t^2-24t+70=0 are t=7,t=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 t^{2} - 24 t + 70 = 0

t = 7, t = 5

Solution steps

2 t^{2} - 24 t + 70 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 70}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 70 = 4

t_{1, 2} = \frac{- ( - 24 ) \pm 4}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 24 ) + 4}{2 \cdot 2}, t_{2} = \frac{- ( - 24 ) - 4}{2 \cdot 2}

t = \frac{- ( - 24 ) + 4}{2 \cdot 2} : 7

t = \frac{- ( - 24 ) - 4}{2 \cdot 2} : 5

The solutions to the quadratic equation are:

t = 7, t = 5

3 \cdot 22

- 6 = \frac{3}{5} y

(160 \cdot 243)^{\frac{1}{5}}

(- 16)^{2}

2 t^{2} + 15 t + 7

What are the solutions to the equation 2t^2-24t+70=0 ?
The solutions to the equation 2t^2-24t+70=0 are t=7,t=5
Find the zeros of 2t^2-24t+70=0
The zeros of 2t^2-24t+70=0 are t=7,t=5