What is factor m^3-7m^2+8m+16 ?

The solution to factor m^3-7m^2+8m+16 is (m+1)(m-4)^2

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factor m^3-7m^2+8m+16

factor

m^{3} - 7 m^{2} + 8 m + 16

(m + 1) (m - 4)^{2}

Solution steps

m^{3} - 7 m^{2} + 8 m + 16

Use the rational root theorem

= (m + 1) \frac{m ^{3} - 7 m ^{2} + 8 m + 16}{m + 1}

\frac{m ^{3} - 7 m ^{2} + 8 m + 16}{m + 1} = m^{2} - 8 m + 16

= (m + 1) (m^{2} - 8 m + 16)

Factor

m^{2} - 8 m + 16 : (m - 4) (m - 4)

= (m + 1) (m - 4) (m - 4)

Apply exponent rule:

aa = a^{2}

(m - 4) (m - 4) = (m - 4)^{2}

= (m + 1) (m - 4)^{2}

x^{2} - 6 x + 9 = 50

- x^{2} - 3 x + 1 = 0

2 (3 w - 8) = 38

\frac{7 ^{2} \cdot 3 \cdot 6 \cdot 12}{2 \cdot 7 ^{2}}

What is factor m^3-7m^2+8m+16 ?
The solution to factor m^3-7m^2+8m+16 is (m+1)(m-4)^2