What are the solutions to the equation r^2+3r+2=0 ?

The solutions to the equation r^2+3r+2=0 are r=-1,r=-2

Find the zeros of r^2+3r+2=0

The zeros of r^2+3r+2=0 are r=-1,r=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 3 r + 2 = 0

r = - 1, r = - 2

Solution steps

r^{2} + 3 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

r_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 3 + 1}{2 \cdot 1}, r_{2} = \frac{- 3 - 1}{2 \cdot 1}

r = \frac{- 3 + 1}{2 \cdot 1} : - 1

r = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

r = - 1, r = - 2

4 (y - 30) = 4 y + 12

12 5^{- \frac{4}{3}}

(39.3 - 84.7)^{2} + (35.3 - 78.7)^{2}

6 x^{2} + x = 15

9 x = 36

What are the solutions to the equation r^2+3r+2=0 ?
The solutions to the equation r^2+3r+2=0 are r=-1,r=-2
Find the zeros of r^2+3r+2=0
The zeros of r^2+3r+2=0 are r=-1,r=-2