What is factor ((3^22^4)^5(12^518^{30})^4)^{-2} ?

The solution to factor ((3^22^4)^5(12^518^{30})^4)^{-2} is 1/(3^{540)*2^{360}}

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factor ((3^22^4)^5(12^518^{30})^4)^{-2}

factor

((3^{2} 2^{4})^{5} (1 2^{5} 1 8^{30})^{4})^{- 2}

\frac{1}{3 ^{540} \cdot 2 ^{360}}

Solution steps

((3^{2} \cdot 2^{4})^{5} (1 2^{5} \cdot 1 8^{30})^{4})^{- 2}

(3^{2} \cdot 2^{4})^{5} = 2^{20} \cdot 3^{10}

= (2^{20} \cdot 3^{10} (1 8^{30} \cdot 1 2^{5})^{4})^{- 2}

(1 2^{5} \cdot 1 8^{30})^{4} = 3^{260} \cdot 2^{160}

= (3^{260} \cdot 2^{160} \cdot 2^{20} \cdot 3^{10})^{- 2}

Simplify

3^{10} \cdot 2^{20} \cdot 2^{160} \cdot 3^{260} : 3^{270} \cdot 2^{180}

= (3^{270} \cdot 2^{180})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 3 ^{270} \cdot 2 ^{180} ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(3^{270} \cdot 2^{180})^{2} = (2^{180})^{2} (3^{270})^{2}

= \frac{1}{( 2 ^{180} ) ^{2} ( 3 ^{270} ) ^{2}}

(2^{180})^{2} : 2^{360}

= \frac{1}{2 ^{360} ( 3 ^{270} ) ^{2}}

(3^{270})^{2} : 3^{540}

= \frac{1}{2 ^{360} \cdot 3 ^{540}}

102 = x 2

a + b - \frac{a - 3}{3}

8 \cdot 7

\frac{1}{x + 7} > 0

- 7 ∣ x + 1 ∣ - 5 = 2 ∣ x + 1 ∣ - 5

What is factor ((3^22^4)^5(12^518^{30})^4)^{-2} ?
The solution to factor ((3^22^4)^5(12^518^{30})^4)^{-2} is 1/(3^{540)*2^{360}}