What are the solutions to the equation u^2+16u+37=0 ?

The solutions to the equation u^2+16u+37=0 are u=-8+3sqrt(3),u=-8-3sqrt(3)

Find the zeros of u^2+16u+37=0

The zeros of u^2+16u+37=0 are u=-8+3sqrt(3),u=-8-3sqrt(3)

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u^{2} + 16 u + 37 = 0

u = - 8 + 33, u = - 8 - 33

Decimal Notation

u = - 2.80384 \dots, u = - 13.19615 \dots

Solution steps

u^{2} + 16 u + 37 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 37 = 63

u_{1, 2} = \frac{- 16 \pm 6 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 16 + 6 3}{2 \cdot 1}, u_{2} = \frac{- 16 - 6 3}{2 \cdot 1}

u = \frac{- 16 + 6 3}{2 \cdot 1} : - 8 + 33

u = \frac{- 16 - 6 3}{2 \cdot 1} : - 8 - 33

The solutions to the quadratic equation are:

u = - 8 + 33, u = - 8 - 33

- x = - 2

(x + 5)^{2} - (x - 5)^{2}

∣ 4 x - 14 ∣ = 6

(a^{\frac{1}{n}})^{m}

x^{2} - 2 x + 1 = 0

What are the solutions to the equation u^2+16u+37=0 ?
The solutions to the equation u^2+16u+37=0 are u=-8+3sqrt(3),u=-8-3sqrt(3)
Find the zeros of u^2+16u+37=0
The zeros of u^2+16u+37=0 are u=-8+3sqrt(3),u=-8-3sqrt(3)