What are the solutions to the equation (x^2+7x)/2 =-5 ?

The solutions to the equation (x^2+7x)/2 =-5 are x=-2,x=-5

Find the zeros of (x^2+7x)/2 =-5

The zeros of (x^2+7x)/2 =-5 are x=-2,x=-5

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\frac{x ^{2} + 7 x}{2} = - 5

x = - 2, x = - 5

Solution steps

\frac{x ^{2} + 7 x}{2} = - 5

Multiply both sides by

2

x^{2} + 7 x = - 10

Move

10

to the left side

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

\frac{3 x}{5} = \frac{x - 2}{4}

1 + (- \frac{12}{5})

4 x + 4 y

(x - 1) (x + 1) = 2 (5 x - 10.5)

8 y - 5 < 3

What are the solutions to the equation (x^2+7x)/2 =-5 ?
The solutions to the equation (x^2+7x)/2 =-5 are x=-2,x=-5
Find the zeros of (x^2+7x)/2 =-5
The zeros of (x^2+7x)/2 =-5 are x=-2,x=-5