What are the solutions to the equation s^2+7s=-15 ?

The solutions to the equation s^2+7s=-15 are s=-7/2+i(sqrt(11))/2 ,s=-7/2-i(sqrt(11))/2

Find the zeros of s^2+7s=-15

The zeros of s^2+7s=-15 are s=-7/2+i(sqrt(11))/2 ,s=-7/2-i(sqrt(11))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} + 7 s = - 15

s = - \frac{7}{2} + i \frac{11}{2}, s = - \frac{7}{2} - i \frac{11}{2}

Solution steps

s^{2} + 7 s = - 15

Move

15

to the left side

s^{2} + 7 s + 15 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

Simplify

7^{2} - 4 \cdot 1 \cdot 15 : 11 i

s_{1, 2} = \frac{- 7 \pm 11 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 7 + 11 i}{2 \cdot 1}, s_{2} = \frac{- 7 - 11 i}{2 \cdot 1}

s = \frac{- 7 + 11 i}{2 \cdot 1} : - \frac{7}{2} + i \frac{11}{2}

s = \frac{- 7 - 11 i}{2 \cdot 1} : - \frac{7}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

s = - \frac{7}{2} + i \frac{11}{2}, s = - \frac{7}{2} - i \frac{11}{2}

\frac{5 π}{4} \cdot \frac{180}{π}

5 x - 3 (2 x - 6) - 3 (x + 2) = 2 x - 6

\frac{x + 3}{x - 5} \leq 0

8 x^{3} + 2 x^{7}

\frac{9}{4} x + 2 = 20

What are the solutions to the equation s^2+7s=-15 ?
The solutions to the equation s^2+7s=-15 are s=-7/2+i(sqrt(11))/2 ,s=-7/2-i(sqrt(11))/2
Find the zeros of s^2+7s=-15
The zeros of s^2+7s=-15 are s=-7/2+i(sqrt(11))/2 ,s=-7/2-i(sqrt(11))/2