What are the solutions to the equation (x-1)^2-25=0 ?

The solutions to the equation (x-1)^2-25=0 are x=6,x=-4

Find the zeros of (x-1)^2-25=0

The zeros of (x-1)^2-25=0 are x=6,x=-4

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(x - 1)^{2} - 25 = 0

x = 6, x = - 4

Solution steps

(x - 1)^{2} - 25 = 0

Move

25

to the right side

(x - 1)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 25 : x = 6

Solve

x - 1 = - 25 : x = - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

- (- \frac{1}{4} x - 3) - 4 x = 7 (\frac{3}{4} x + 1) + 6

- \frac{4}{8}

25 y^{2} x^{2} + 30 y x^{2} + 9 x^{2}

3 x + 12 = - 6

7 x (x^{2} + y^{2}) - (x^{2} + y^{2}) - 3 y (x^{2} + y^{2})

What are the solutions to the equation (x-1)^2-25=0 ?
The solutions to the equation (x-1)^2-25=0 are x=6,x=-4
Find the zeros of (x-1)^2-25=0
The zeros of (x-1)^2-25=0 are x=6,x=-4