What are the solutions to the equation 2x^2+6x-20=0 ?

The solutions to the equation 2x^2+6x-20=0 are x=2,x=-5

Find the zeros of 2x^2+6x-20=0

The zeros of 2x^2+6x-20=0 are x=2,x=-5

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2 x^{2} + 6 x - 20 = 0

x = 2, x = - 5

Solution steps

2 x^{2} + 6 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 20) = 14

x_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 14}{2 \cdot 2}, x_{2} = \frac{- 6 - 14}{2 \cdot 2}

x = \frac{- 6 + 14}{2 \cdot 2} : 2

x = \frac{- 6 - 14}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

- (\frac{7}{3})^{0}

- 4 x^{2} - 42 x - 98 = - 2 x - 2

\frac{2 x}{5} - \frac{1}{3} = \frac{137}{3}

- \frac{1}{5} - (- \frac{2}{9})

ln (5 - 7 x) \leq 1

What are the solutions to the equation 2x^2+6x-20=0 ?
The solutions to the equation 2x^2+6x-20=0 are x=2,x=-5
Find the zeros of 2x^2+6x-20=0
The zeros of 2x^2+6x-20=0 are x=2,x=-5