What are the solutions to the equation 1500=x^2+20x ?

The solutions to the equation 1500=x^2+20x are x=30,x=-50

Find the zeros of 1500=x^2+20x

The zeros of 1500=x^2+20x are x=30,x=-50

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1500 = x^{2} + 20 x

x = 30, x = - 50

Solution steps

1500 = x^{2} + 20 x

Switch sides

x^{2} + 20 x = 1500

Move

1500

to the left side

x^{2} + 20 x - 1500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 1500 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 1500) = 80

x_{1, 2} = \frac{- 20 \pm 80}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 80}{2 \cdot 1}, x_{2} = \frac{- 20 - 80}{2 \cdot 1}

x = \frac{- 20 + 80}{2 \cdot 1} : 30

x = \frac{- 20 - 80}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 30, x = - 50

∣ - x - 3 ∣ = 5

3 x^{2} - 7 x + 1 = 0

lo g_{3} (21) = 4 x

- 1.2 (3)^{2} + 9.6 (3)

4 x^{3} - 16 x < 0

What are the solutions to the equation 1500=x^2+20x ?
The solutions to the equation 1500=x^2+20x are x=30,x=-50
Find the zeros of 1500=x^2+20x
The zeros of 1500=x^2+20x are x=30,x=-50