en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4<= |x+2|

Solution

4 \leq ∣ x + 2 ∣

Solution

x \leq - 6 or x \geq 2

+1

Interval Notation

(- \infty, - 6] \cup [2, \infty)

Solution steps

4 \leq ∣ x + 2 ∣

Switch sides

∣ x + 2 ∣ \geq 4

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 2 \leq - 4 or x + 2 \geq 4

x + 2 \leq - 4 or x + 2 \geq 4

x \leq - 6 or x \geq 2

Popular Examples

factor-81+9a^{10}factor

- 81 + 9 a^{10}

factor x^2+17x+52 factor

x^{2} + 17 x + 52

simplify (4/5)^2-(3/5)^2 simplify

(\frac{4}{5})^{2} - (\frac{3}{5})^{2}

factor 70y^8+30y^6 factor

70 y^{8} + 30 y^{6}

simplify ((-1+5i))/(2+3i)simplify

\frac{( - 1 + 5 i )}{2 + 3 i}

Frequently Asked Questions (FAQ)

What is 4<= |x+2| ?
The solution to 4<= |x+2| is x<=-6\lor x>= 2