What is 1/(sqrt(x+4))>= 0 ?

The solution to 1/(sqrt(x+4))>= 0 is x>-4

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1/(sqrt(x+4))>= 0

\frac{1}{x + 4} \geq 0

x > - 4

Interval Notation

(- 4, \infty)

Solution steps

\frac{1}{x + 4} \geq 0

\frac{1}{a} \geq 0

then

a > 0

x + 4 > 0

Square both sides

(x + 4)^{2} > 0^{2}

Simplify

x + 4 > 0

Move

4

to the right side

x > - 4

Find singularity points

Find non-negative values for radicals:

x \geq - 4

Combine the intervals

x > - 4 and x \geq - 4

Merge Overlapping Intervals

x > - 4

Find singularity points

Find non-negative values for radicals:

x \geq - 4

Combine the intervals

x > - 4 and x \geq - 4

Merge Overlapping Intervals

x > - 4

19 \cdot 7

x (x - 1) (x + 5) > 0

122

\frac{4 x + 8}{8} = \frac{- 3 x + 12}{3}

(2)^{4}