What are the solutions to the equation -4x^2+12x-9=0x ?

The solutions to the equation -4x^2+12x-9=0x are x= 3/2

Find the zeros of -4x^2+12x-9=0x

The zeros of -4x^2+12x-9=0x are x= 3/2

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- 4 x^{2} + 12 x - 9 = 0 x

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

- 4 x^{2} + 12 x - 9 = 0 \cdot x

Refine

- 4 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

1 2^{2} - 4 (- 4) (- 9) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 4 )}

x = \frac{- 12}{2 ( - 4 )}

\frac{- 12}{2 ( - 4 )} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

2 \frac{π}{\frac{1}{2}}

\frac{5 !}{( 5 - 3 ) ! 3 !}

5 + x = 26

\frac{n}{6.8} = - 19.1

x^{2} + 8 x - 33 = 0

What are the solutions to the equation -4x^2+12x-9=0x ?
The solutions to the equation -4x^2+12x-9=0x are x= 3/2
Find the zeros of -4x^2+12x-9=0x
The zeros of -4x^2+12x-9=0x are x= 3/2