What is |x^2-12|>= 4x ?

The solution to |x^2-12|>= 4x is x = 6

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|x^2-12|>= 4x

x^{2} - 12 \geq 4 x

x \leq 2 or x \geq 6

Interval Notation

(- \infty, 2] \cup [6, \infty)

Solution steps

x^{2} - 12 \geq 4 x

Find positive and negative intervals

x \leq - 23, - 23 < x < 23, x \geq 23

Solve the inequality for each interval

x \leq - 23 or - 23 < x \leq 2 or x \geq 6

Merge Overlapping Intervals

x \leq 2 or x \geq 6

3 x^{2} + 12 x + 9 = 0

1 + b^{3}

\frac{25}{36}

x^{2} + 4 x = 10 + x

9 x^{3} - 6 x^{2} y + x y^{2}