What are the solutions to the equation 1/3 (x+4)^2=48 ?

The solutions to the equation 1/3 (x+4)^2=48 are x=8,x=-16

Find the zeros of 1/3 (x+4)^2=48

The zeros of 1/3 (x+4)^2=48 are x=8,x=-16

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\frac{1}{3} (x + 4)^{2} = 48

x = 8, x = - 16

Solution steps

\frac{1}{3} (x + 4)^{2} = 48

Multiply both sides by

3

(x + 4)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 144 : x = 8

Solve

x + 4 = - 144 : x = - 16

The solutions to the quadratic equation are:

x = 8, x = - 16

2 x = x - 4

- 13 = 6 x + 5

(4 + 3 i) (4 + 2 i) (3 - i) (1 - i)

m^{2} - 12 m + 20

7 + 4 y = 7 - 5 y + 54

What are the solutions to the equation 1/3 (x+4)^2=48 ?
The solutions to the equation 1/3 (x+4)^2=48 are x=8,x=-16
Find the zeros of 1/3 (x+4)^2=48
The zeros of 1/3 (x+4)^2=48 are x=8,x=-16