What is factor 42x^3-7x^2+28x ?

The solution to factor 42x^3-7x^2+28x is 7x(6x^2-x+4)

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factor 42x^3-7x^2+28x

factor

42 x^{3} - 7 x^{2} + 28 x

7 x (6 x^{2} - x + 4)

Solution steps

42 x^{3} - 7 x^{2} + 28 x

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{2} = xx

= 42 x^{2} x - 7 xx + 28 x

Rewrite

42

7 \cdot 6

Rewrite

28

7 \cdot 4

= 7 \cdot 6 x^{2} x - 7 xx + 7 \cdot 4 x

Factor out common term

7 x

= 7 x (6 x^{2} - x + 4)

∣ 6 m ∣ = 42

(2 x)^{2}

(2^{3} + 1^{3})^{\frac{1}{3}} = 2 + 1

24 x^{3} - 26 x^{2} - 83 x + 45

10 c + 2 (8 c + 10) < c - 8 - 7

What is factor 42x^3-7x^2+28x ?
The solution to factor 42x^3-7x^2+28x is 7x(6x^2-x+4)