What are the solutions to the equation 2x^2+3x-1=0 ?

The solutions to the equation 2x^2+3x-1=0 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4

Find the zeros of 2x^2+3x-1=0

The zeros of 2x^2+3x-1=0 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4

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2 x^{2} + 3 x - 1 = 0

x = \frac{- 3 + 17}{4}, x = \frac{- 3 - 17}{4}

Decimal Notation

x = 0.28077 \dots, x = - 1.78077 \dots

Solution steps

2 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 1) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 2}, x_{2} = \frac{- 3 - 17}{2 \cdot 2}

x = \frac{- 3 + 17}{2 \cdot 2} : \frac{- 3 + 17}{4}

x = \frac{- 3 - 17}{2 \cdot 2} : \frac{- 3 - 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 17}{4}, x = \frac{- 3 - 17}{4}

(2 c^{- 1})^{- 3}

\frac{b ^{2} + 3 b - 28}{b ^{2} - 49}

2.08 \geq 0.65 y

4 x - 7 \leq x - 1 < 3 x + 7

- 2 + \frac{16}{3}

What are the solutions to the equation 2x^2+3x-1=0 ?
The solutions to the equation 2x^2+3x-1=0 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4
Find the zeros of 2x^2+3x-1=0
The zeros of 2x^2+3x-1=0 are x=(-3+sqrt(17))/4 ,x=(-3-sqrt(17))/4