What are the solutions to the equation 2x^2+4x-11=0 ?

The solutions to the equation 2x^2+4x-11=0 are x=(-2+sqrt(26))/2 ,x=-(2+sqrt(26))/2

Find the zeros of 2x^2+4x-11=0

The zeros of 2x^2+4x-11=0 are x=(-2+sqrt(26))/2 ,x=-(2+sqrt(26))/2

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2 x^{2} + 4 x - 11 = 0

x = \frac{- 2 + 26}{2}, x = - \frac{2 + 26}{2}

Decimal Notation

x = 1.54950 \dots, x = - 3.54950 \dots

Solution steps

2 x^{2} + 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 11) = 226

x_{1, 2} = \frac{- 4 \pm 2 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 26}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 26}{2 \cdot 2}

x = \frac{- 4 + 2 26}{2 \cdot 2} : \frac{- 2 + 26}{2}

x = \frac{- 4 - 2 26}{2 \cdot 2} : - \frac{2 + 26}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 26}{2}, x = - \frac{2 + 26}{2}

4 x^{2} + 36 x + 72

\frac{( 3 \cdot 1 0 ^{4} ) ( 5 \cdot 1 0 ^{- 2} )}{2 \cdot 1 0 ^{5}}

∣ 5 y - 8 ∣ = ∣ 8 - 5 y ∣

37 = - 3 + 5 (x + 6)

\frac{m ^{2} - 1}{m - 1}

What are the solutions to the equation 2x^2+4x-11=0 ?
The solutions to the equation 2x^2+4x-11=0 are x=(-2+sqrt(26))/2 ,x=-(2+sqrt(26))/2
Find the zeros of 2x^2+4x-11=0
The zeros of 2x^2+4x-11=0 are x=(-2+sqrt(26))/2 ,x=-(2+sqrt(26))/2