What is (25x^2-49)/(x^2-36)<= 0 ?

The solution to (25x^2-49)/(x^2-36)<= 0 is -6<x<=-7/5 \lor 7/5 <= x<6

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(25x^2-49)/(x^2-36)<= 0

\frac{25 x ^{2} - 49}{x ^{2} - 36} \leq 0

- 6 < x \leq - \frac{7}{5} or \frac{7}{5} \leq x < 6

Interval Notation

(- 6, - \frac{7}{5}] \cup [\frac{7}{5}, 6)

Decimal Notation

- 6 < x \leq - 1.4 or 1.4 \leq x < 6

Solution steps

\frac{25 x ^{2} - 49}{x ^{2} - 36} \leq 0

Factor

\frac{25 x ^{2} - 49}{x ^{2} - 36} : \frac{( 5 x + 7 ) ( 5 x - 7 )}{( x + 6 ) ( x - 6 )}

\frac{( 5 x + 7 ) ( 5 x - 7 )}{( x + 6 ) ( x - 6 )} \leq 0

Identify the intervals

- 6 < x \leq - \frac{7}{5} or \frac{7}{5} \leq x < 6

24 \cdot 8

\frac{x - 1}{x ^{2} - 4} < 0

\frac{5}{2 - 1}

- 4.75 = \frac{z}{2}

x^{2} (6 x + 11) > 3 x + 2

What is (25x^2-49)/(x^2-36)<= 0 ?
The solution to (25x^2-49)/(x^2-36)<= 0 is -6<x<=-7/5 \lor 7/5 <= x<6