What are the solutions to the equation x^2+10x=-26 ?

The solutions to the equation x^2+10x=-26 are x=-5+i,x=-5-i

Find the zeros of x^2+10x=-26

The zeros of x^2+10x=-26 are x=-5+i,x=-5-i

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x^{2} + 10 x = - 26

x = - 5 + i, x = - 5 - i

Solution steps

x^{2} + 10 x = - 26

Move

26

to the left side

x^{2} + 10 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 26 : 2 i

x_{1, 2} = \frac{- 10 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 i}{2 \cdot 1}

x = \frac{- 10 + 2 i}{2 \cdot 1} : - 5 + i

x = \frac{- 10 - 2 i}{2 \cdot 1} : - 5 - i

The solutions to the quadratic equation are:

x = - 5 + i, x = - 5 - i

\frac{125}{2}

2 (4 z - 2) = 44

15 m^{2} + 11 m - 14

45 x y^{6} - 20 y^{4} z^{4}

3 x^{2} + 10 x \geq 8

What are the solutions to the equation x^2+10x=-26 ?
The solutions to the equation x^2+10x=-26 are x=-5+i,x=-5-i
Find the zeros of x^2+10x=-26
The zeros of x^2+10x=-26 are x=-5+i,x=-5-i