What are the solutions to the equation (x-2)(3x-1)=0 ?

The solutions to the equation (x-2)(3x-1)=0 are x=2,x= 1/3

Find the zeros of (x-2)(3x-1)=0

The zeros of (x-2)(3x-1)=0 are x=2,x= 1/3

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(x - 2) (3 x - 1) = 0

x = 2, x = \frac{1}{3}

Decimal Notation

x = 2, x = 0.33333 \dots

Solution steps

(x - 2) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{3}

(5^{8})^{2}

- 2 x^{2} < 0

x^{2} y^{2} - 1

(x + 2) (x - 2) + 16 = (x + 2)^{2} + (x - 2)^{2}

- 2 x + 7 = 0

What are the solutions to the equation (x-2)(3x-1)=0 ?
The solutions to the equation (x-2)(3x-1)=0 are x=2,x= 1/3
Find the zeros of (x-2)(3x-1)=0
The zeros of (x-2)(3x-1)=0 are x=2,x= 1/3