What are the solutions to the equation 2x^2-10x+7=0 ?

The solutions to the equation 2x^2-10x+7=0 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2

Find the zeros of 2x^2-10x+7=0

The zeros of 2x^2-10x+7=0 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2

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2 x^{2} - 10 x + 7 = 0

x = \frac{5 + 11}{2}, x = \frac{5 - 11}{2}

Decimal Notation

x = 4.15831 \dots, x = 0.84168 \dots

Solution steps

2 x^{2} - 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 7 = 211

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 11}{2 \cdot 2} : \frac{5 + 11}{2}

x = \frac{- ( - 10 ) - 2 11}{2 \cdot 2} : \frac{5 - 11}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 11}{2}, x = \frac{5 - 11}{2}

x + 2 x + 7 = 3 x - 7

\frac{100}{64}

54 + 34 = 49 x + 23 - 84 x

∣ x + 4 ∣ + 8 = 3 x

1 - \frac{1}{5} x = - \frac{4}{5} (5 + x)

What are the solutions to the equation 2x^2-10x+7=0 ?
The solutions to the equation 2x^2-10x+7=0 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2
Find the zeros of 2x^2-10x+7=0
The zeros of 2x^2-10x+7=0 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2