What is factor 5x^4-2x^2+20x^2-8 ?

The solution to factor 5x^4-2x^2+20x^2-8 is (5x^2-2)(x^2+4)

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factor 5x^4-2x^2+20x^2-8

factor

5 x^{4} - 2 x^{2} + 20 x^{2} - 8

(5 x^{2} - 2) (x^{2} + 4)

Solution steps

5 x^{4} - 2 x^{2} + 20 x^{2} - 8

Add similar elements:

- 2 x^{2} + 20 x^{2} = 18 x^{2}

= 5 x^{4} + 18 x^{2} - 8

Let

u = x^{2}

= 5 u^{2} + 18 u - 8

Factor

5 u^{2} + 18 u - 8 : (5 u - 2) (u + 4)

= (5 u - 2) (u + 4)

Substitute back

u = x^{2}

= (5 x^{2} - 2) (x^{2} + 4)

8 n^{2} + 71 n - 90

x^{2} + 10 x + 21 \geq 0

(x - 7)^{2} = 4

\frac{( a ^{- 2} )}{( a ^{5} )}

\frac{4}{\frac{1}{3}}

What is factor 5x^4-2x^2+20x^2-8 ?
The solution to factor 5x^4-2x^2+20x^2-8 is (5x^2-2)(x^2+4)