What are the solutions to the equation X^2+X-3=0 ?

The solutions to the equation X^2+X-3=0 are X=(-1+sqrt(13))/2 ,X=(-1-sqrt(13))/2

Find the zeros of X^2+X-3=0

The zeros of X^2+X-3=0 are X=(-1+sqrt(13))/2 ,X=(-1-sqrt(13))/2

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X^{2} + X - 3 = 0

X = \frac{- 1 + 13}{2}, X = \frac{- 1 - 13}{2}

Decimal Notation

X = 1.30277 \dots, X = - 2.30277 \dots

Solution steps

X^{2} + X - 3 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 3) = 13

X_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 1 + 13}{2 \cdot 1}, X_{2} = \frac{- 1 - 13}{2 \cdot 1}

X = \frac{- 1 + 13}{2 \cdot 1} : \frac{- 1 + 13}{2}

X = \frac{- 1 - 13}{2 \cdot 1} : \frac{- 1 - 13}{2}

The solutions to the quadratic equation are:

X = \frac{- 1 + 13}{2}, X = \frac{- 1 - 13}{2}

lo g_{36} (6)

(- a^{2} - 5 ab + 3 b^{2}) - (3 a^{2} - 2 ab + 3 b^{2})

\frac{1}{2} \cdot \frac{3}{4}

3 a^{2} b^{2} - 6 a^{2} b

43 \cdot 4

What are the solutions to the equation X^2+X-3=0 ?
The solutions to the equation X^2+X-3=0 are X=(-1+sqrt(13))/2 ,X=(-1-sqrt(13))/2
Find the zeros of X^2+X-3=0
The zeros of X^2+X-3=0 are X=(-1+sqrt(13))/2 ,X=(-1-sqrt(13))/2