What is factor t^2+9t+18 ?

The solution to factor t^2+9t+18 is (t+3)(t+6)

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factor t^2+9t+18

factor

t^{2} + 9 t + 18

(t + 3) (t + 6)

Solution steps

t^{2} + 9 t + 18

Break the expression into groups

= (t^{2} + 3 t) + (6 t + 18)

Factor out

t

from

t^{2} + 3 t : t (t + 3)

Factor out

6

from

6 t + 18 : 6 (t + 3)

= t (t + 3) + 6 (t + 3)

Factor out common term

t + 3

= (t + 3) (t + 6)

2 x - 1 = x^{2}

3 (2 x + 2) > 24 - 4 x

v^{2} - 49

2^{x + 2} - 2^{x + 1} + 2^{x - 1} - 2^{x - 2} \leq 9

c^{2} - 12 c + 35