What is factor 16yx^4+12y^3x^2-20yx ?

The solution to factor 16yx^4+12y^3x^2-20yx is 4yx(4x^3+3y^2x-5)

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factor 16yx^4+12y^3x^2-20yx

factor

16 y x^{4} + 12 y^{3} x^{2} - 20 y x

4 y x (4 x^{3} + 3 y^{2} x - 5)

Solution steps

16 y x^{4} + 12 y^{3} x^{2} - 20 y x

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

y x^{4} = y x x^{3}, y^{3} x^{2} = y y^{2} xx

= 16 y x x^{3} + 12 y y^{2} xx - 20 y x

Rewrite

- 20

5 \cdot 4

Rewrite

12

3 \cdot 4

= 4 \cdot 4 y x x^{3} + 3 \cdot 4 y y^{2} xx + 5 \cdot 4 y x

Factor out common term

4 y x

= 4 y x (4 x^{3} + 3 y^{2} x - 5)

∣ w ∣ = 0

(x + 3)^{3}

\frac{- 1}{2} < \frac{2 x + 3}{5} < \frac{3}{2}

∣ x + 5 ∣ \leq 8

4 \cdot 60

What is factor 16yx^4+12y^3x^2-20yx ?
The solution to factor 16yx^4+12y^3x^2-20yx is 4yx(4x^3+3y^2x-5)