What are the solutions to the equation 2x^2-11x=21 ?

The solutions to the equation 2x^2-11x=21 are x=7,x=-3/2

Find the zeros of 2x^2-11x=21

The zeros of 2x^2-11x=21 are x=7,x=-3/2

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2 x^{2} - 11 x = 21

x = 7, x = - \frac{3}{2}

Decimal Notation

x = 7, x = - 1.5

Solution steps

2 x^{2} - 11 x = 21

Move

21

to the left side

2 x^{2} - 11 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 21) = 17

x_{1, 2} = \frac{- ( - 11 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 17}{2 \cdot 2}

x = \frac{- ( - 11 ) + 17}{2 \cdot 2} : 7

x = \frac{- ( - 11 ) - 17}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{3}{2}

5 x + 8 < 2 x + 3

- 5 \leq \frac{x - 3}{3} \leq 1

- 5 x^{2} + 600 x - 18000 \geq 0

18 - x - 7 = 0

\frac{7}{3} \cdot (\frac{2}{3} - \frac{2}{9})

What are the solutions to the equation 2x^2-11x=21 ?
The solutions to the equation 2x^2-11x=21 are x=7,x=-3/2
Find the zeros of 2x^2-11x=21
The zeros of 2x^2-11x=21 are x=7,x=-3/2