What are the solutions to the equation 9x^2+81=0 ?

The solutions to the equation 9x^2+81=0 are x=3i,x=-3i

Find the zeros of 9x^2+81=0

The zeros of 9x^2+81=0 are x=3i,x=-3i

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9 x^{2} + 81 = 0

x = 3 i, x = - 3 i

Solution steps

9 x^{2} + 81 = 0

Move

81

to the right side

9 x^{2} = - 81

Divide both sides by

9

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

0.5 (x - 1)^{2} = 0.8 (4 - x)^{2}

∣ 5 - p ∣ + 13 > 6

x^{2} - 7 x + 6 \leq 0

\frac{3 x - 23}{4} = - 2

6 n^{2} - 18 n - 24 = 0

What are the solutions to the equation 9x^2+81=0 ?
The solutions to the equation 9x^2+81=0 are x=3i,x=-3i
Find the zeros of 9x^2+81=0
The zeros of 9x^2+81=0 are x=3i,x=-3i