What are the solutions to the equation x^2-2x=24 ?

The solutions to the equation x^2-2x=24 are x=6,x=-4

Find the zeros of x^2-2x=24

The zeros of x^2-2x=24 are x=6,x=-4

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x^{2} - 2 x = 24

x = 6, x = - 4

Solution steps

x^{2} - 2 x = 24

Move

24

to the left side

x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

x = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

360 + 45 + x = 675

- x + 5 > \frac{x}{4}

\frac{3}{3 ^{- 1}}

5^{2} + 4^{2} = c^{2}

2 x^{3} y + 4 x^{2} y^{3}

What are the solutions to the equation x^2-2x=24 ?
The solutions to the equation x^2-2x=24 are x=6,x=-4
Find the zeros of x^2-2x=24
The zeros of x^2-2x=24 are x=6,x=-4