What is ((a^2-b^{(2)}))/(a+b)-(a+b)^2+2(a^2+ab) ?

The solution to ((a^2-b^{(2)}))/(a+b)-(a+b)^2+2(a^2+ab) is a^2+a-b^2-b

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simplify ((a^2-b^{(2)}))/(a+b)-(a+b)^2+2(a^2+ab)

simplify

\frac{( a ^{2} - b ^{(2)} )}{a + b} - (a + b)^{2} + 2 (a^{2} + ab)

a^{2} + a - b^{2} - b

Solution steps

\frac{a ^{2} - b ^{2}}{a + b} - (a + b)^{2} + 2 (a^{2} + ab)

Cancel

\frac{a ^{2} - b ^{2}}{a + b} : a - b

= a - b - (a + b)^{2} + 2 (a^{2} + ab)

Expand

- (a + b)^{2} : - a^{2} - 2 ab - b^{2}

= a - b - a^{2} - 2 ab - b^{2} + 2 (a^{2} + ab)

Expand

2 (a^{2} + ab) : 2 a^{2} + 2 ab

= a - b - a^{2} - 2 ab - b^{2} + 2 a^{2} + 2 ab

Group like terms

= - a^{2} + 2 a^{2} + a - b^{2} - b - 2 ab + 2 ab

Add similar elements:

- a^{2} + 2 a^{2} = a^{2}

= a^{2} + a - b^{2} - b - 2 ab + 2 ab

Add similar elements:

- 2 ab + 2 ab = 0

= a^{2} + a - b^{2} - b

8^{\frac{- 1}{3}}

\frac{x}{7} = \frac{x}{6} - 2

\frac{8}{12} + \frac{2}{5} - \frac{1}{2} - \frac{1}{10}

(y - \frac{3}{x})^{2}

k^{2} - 64

What is ((a^2-b^{(2)}))/(a+b)-(a+b)^2+2(a^2+ab) ?
The solution to ((a^2-b^{(2)}))/(a+b)-(a+b)^2+2(a^2+ab) is a^2+a-b^2-b