What are the solutions to the equation (z-6)^2=18 ?

The solutions to the equation (z-6)^2=18 are z=3sqrt(2)+6,z=-3sqrt(2)+6

Find the zeros of (z-6)^2=18

The zeros of (z-6)^2=18 are z=3sqrt(2)+6,z=-3sqrt(2)+6

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(z - 6)^{2} = 18

z = 32 + 6, z = - 32 + 6

Decimal Notation

z = 10.24264 \dots, z = 1.75735 \dots

Solution steps

(z - 6)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z - 6 = 18 : z = 32 + 6

Solve

z - 6 = - 18 : z = - 32 + 6

The solutions to the quadratic equation are:

z = 32 + 6, z = - 32 + 6

81 - 25 x^{2}

∣ 3 x ∣ > 6

\frac{1}{x - 10} \leq \frac{x}{x + 2}

7 b - 15 = 5 b - 3

8 x - 12 = 4 (\frac{1}{2} x - 6)

What are the solutions to the equation (z-6)^2=18 ?
The solutions to the equation (z-6)^2=18 are z=3sqrt(2)+6,z=-3sqrt(2)+6
Find the zeros of (z-6)^2=18
The zeros of (z-6)^2=18 are z=3sqrt(2)+6,z=-3sqrt(2)+6