What is the answer to x(x^2+x)-(x+1)(x^2-2)=-4 ?

The answer to x(x^2+x)-(x+1)(x^2-2)=-4 is x=-3

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x(x^2+x)-(x+1)(x^2-2)=-4

x (x^{2} + x) - (x + 1) (x^{2} - 2) = - 4

x = - 3

Solution steps

x (x^{2} + x) - (x + 1) (x^{2} - 2) = - 4

Expand

x (x^{2} + x) - (x + 1) (x^{2} - 2) : 2 x + 2

2 x + 2 = - 4

Move

2

to the right side

2 x = - 6

Divide both sides by

2

x = - 3

2 x^{2} - 50 y^{2}

\frac{\frac{2 a - b}{b} + 1}{\frac{2 a + b}{b} - 1}

2 x < 5 - 3 x \leq 6 x + 8

x^{2} + 0.506 x + 0.22 = 0

\frac{x}{15} + x = \frac{2 x}{5} + 10

What is the answer to x(x^2+x)-(x+1)(x^2-2)=-4 ?
The answer to x(x^2+x)-(x+1)(x^2-2)=-4 is x=-3
Solve for x: x(x^2+x)-(x+1)(x^2-2)=-4
The solution is x=-3