What is (4+i)-(3-5i)(-2+5i) ?

The solution to (4+i)-(3-5i)(-2+5i) is -15-24i

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simplify (4+i)-(3-5i)(-2+5i)

simplify

(4 + i) - (3 - 5 i) (- 2 + 5 i)

- 15 - 24 i

Solution steps

(4 + i) - (3 - 5 i) (- 2 + 5 i)

Apply rule:

(a) = a

(4 + i) = 4 + i

= 4 + i - (3 - 5 i) (- 2 + 5 i)

(3 - 5 i) (- 2 + 5 i) = 19 + 25 i

= 4 + i - 19 + 25 i

Expand

- (19 + 25 i) : - 19 - 25 i

= 4 + i - 19 - 25 i

Group like terms

= i - 25 i + 4 - 19

Add similar elements:

i - 25 i = - 24 i

= - 24 i + 4 - 19

Subtract the numbers:

4 - 19 = - 15

= - 24 i - 15

Rewrite in standard complex form:

- 15 - 24 i

= - 15 - 24 i

5 x < 10

x (x - 2)^{2} > 0

lo g_{7} (0)

\frac{e ^{0}}{2}

(x - 3) (x + 5) = x - 2