What is factor b^2-7b+6 ?

The solution to factor b^2-7b+6 is (b-1)(b-6)

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factor b^2-7b+6

factor

b^{2} - 7 b + 6

(b - 1) (b - 6)

Solution steps

b^{2} - 7 b + 6

Break the expression into groups

= (b^{2} - b) + (- 6 b + 6)

Factor out

b

from

b^{2} - b : b (b - 1)

Factor out

- 6

from

- 6 b + 6 : - 6 (b - 1)

= b (b - 1) - 6 (b - 1)

Factor out common term

b - 1

= (b - 1) (b - 6)

8^{- 2} = \frac{1}{64}

(- 4 x y)^{3} (- 2 x^{2})^{3}

13 x - 5 (x + 2) = 4 (2 x - 1) + 7

\frac{1}{x - 1} \leq 1

4 x^{4} - 5 x^{2} y^{2} - 2 x^{3}