What are the solutions to the equation 5x^2+26x+24=0 ?

The solutions to the equation 5x^2+26x+24=0 are x=-6/5 ,x=-4

Find the zeros of 5x^2+26x+24=0

The zeros of 5x^2+26x+24=0 are x=-6/5 ,x=-4

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5 x^{2} + 26 x + 24 = 0

x = - \frac{6}{5}, x = - 4

Decimal Notation

x = - 1.2, x = - 4

Solution steps

5 x^{2} + 26 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 \cdot 24}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 \cdot 24 = 14

x_{1, 2} = \frac{- 26 \pm 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 26 + 14}{2 \cdot 5}, x_{2} = \frac{- 26 - 14}{2 \cdot 5}

x = \frac{- 26 + 14}{2 \cdot 5} : - \frac{6}{5}

x = \frac{- 26 - 14}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = - \frac{6}{5}, x = - 4

\frac{m}{4} = \frac{m}{3} - 2

(3)^{2} \cdot (4)^{3} \cdot (5)^{4}

\frac{10}{8} < \frac{y + 4}{4} < \frac{16}{8}

3 x^{2} + 33 x + 90

14 - 6 b = 2 + 6 b

What are the solutions to the equation 5x^2+26x+24=0 ?
The solutions to the equation 5x^2+26x+24=0 are x=-6/5 ,x=-4
Find the zeros of 5x^2+26x+24=0
The zeros of 5x^2+26x+24=0 are x=-6/5 ,x=-4