What are the solutions to the equation z^2+11z+9=5z ?

The solutions to the equation z^2+11z+9=5z are z=-3

Find the zeros of z^2+11z+9=5z

The zeros of z^2+11z+9=5z are z=-3

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z^{2} + 11 z + 9 = 5 z

z = - 3

Solution steps

z^{2} + 11 z + 9 = 5 z

Move

5 z

to the left side

z^{2} + 6 z + 9 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

z_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

z = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

z = - 3

The solution to the quadratic equation is:

z = - 3

\frac{3}{2} = \frac{g}{57}

144 \cdot 6 - 4 (x + 6) (36 - 4 x) = 0

n + 3 \geq 9

∣ x + 2 ∣ + 5 < 4

∣ x ∣ \leq 8

What are the solutions to the equation z^2+11z+9=5z ?
The solutions to the equation z^2+11z+9=5z are z=-3
Find the zeros of z^2+11z+9=5z
The zeros of z^2+11z+9=5z are z=-3