What is ((12xy^7)/(4x^4y^3))^2 ?

The solution to ((12xy^7)/(4x^4y^3))^2 is (9y^8)/(x^6)

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simplify ((12xy^7)/(4x^4y^3))^2

simplify

(\frac{12 x y ^{7}}{4 x ^{4} y ^{3}})^{2}

\frac{9 y ^{8}}{x ^{6}}

Solution steps

(\frac{12 x y ^{7}}{4 x ^{4} y ^{3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 12 x y ^{7} ) ^{2}}{( 4 x ^{4} y ^{3} ) ^{2}}

Simplify

(12 x y^{7})^{2} : 144 x^{2} y^{14}

= \frac{144 x ^{2} y ^{14}}{( 4 x ^{4} y ^{3} ) ^{2}}

Simplify

(4 x^{4} y^{3})^{2} : 16 x^{8} y^{6}

= \frac{144 x ^{2} y ^{14}}{16 x ^{8} y ^{6}}

Divide the numbers:

\frac{144}{16} = 9

= \frac{9 x ^{2} y ^{14}}{x ^{8} y ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{2}}{x ^{8}} = \frac{1}{x ^{8 - 2}}

= \frac{9 y ^{14}}{y ^{6} x ^{8 - 2}}

Subtract the numbers:

8 - 2 = 6

= \frac{9 y ^{14}}{x ^{6} y ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{14}}{y ^{6}} = y^{14 - 6}

= \frac{9 y ^{14 - 6}}{x ^{6}}

Subtract the numbers:

14 - 6 = 8

= \frac{9 y ^{8}}{x ^{6}}

3 x^{2} - 22 x + 39 = 0

- 4 T + 8 - 6 T = - 4 - 10 T + 3

(x \cdot y)^{\frac{3}{4}}

\frac{x}{- 7} < 14

10 \cdot 972

What is ((12xy^7)/(4x^4y^3))^2 ?
The solution to ((12xy^7)/(4x^4y^3))^2 is (9y^8)/(x^6)