What is 4(p-6p^2q)-9-9pq+7p(p+q)-5(3+pq) ?

The solution to 4(p-6p^2q)-9-9pq+7p(p+q)-5(3+pq) is 4p-24p^2q+7p^2-7pq-24

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simplify 4(p-6p^2q)-9-9pq+7p(p+q)-5(3+pq)

simplify

4 (p - 6 p^{2} q) - 9 - 9 pq + 7 p (p + q) - 5 (3 + pq)

4 p - 24 p^{2} q + 7 p^{2} - 7 pq - 24

Solution steps

4 (p - 6 p^{2} q) - 9 - 9 pq + 7 p (p + q) - 5 (3 + pq)

Expand

4 (p - 6 p^{2} q) : 4 p - 24 p^{2} q

= 4 p - 24 p^{2} q - 9 - 9 pq + 7 p (p + q) - 5 (3 + pq)

Expand

7 p (p + q) : 7 p^{2} + 7 pq

= 4 p - 24 p^{2} q - 9 - 9 pq + 7 p^{2} + 7 pq - 5 (3 + pq)

Expand

- 5 (3 + pq) : - 15 - 5 pq

= 4 p - 24 p^{2} q - 9 - 9 pq + 7 p^{2} + 7 pq - 15 - 5 pq

Group like terms

= 4 p - 24 p^{2} q + 7 p^{2} - 9 pq + 7 pq - 5 pq - 9 - 15

Add similar elements:

- 9 pq + 7 pq - 5 pq = - 7 pq

= 4 p - 24 p^{2} q + 7 p^{2} - 7 pq - 9 - 15

Subtract the numbers:

- 9 - 15 = - 24

= 4 p - 24 p^{2} q + 7 p^{2} - 7 pq - 24

x^{2} - 18 x - 4 = 0

(1 + i) (1 - i)

∣ x ∣ > 11

\frac{2 b a ^{3}}{7} - \frac{a b ^{3}}{5}

- 121

What is 4(p-6p^2q)-9-9pq+7p(p+q)-5(3+pq) ?
The solution to 4(p-6p^2q)-9-9pq+7p(p+q)-5(3+pq) is 4p-24p^2q+7p^2-7pq-24