What are the solutions to the equation 4x^2-12x+5=0 ?

The solutions to the equation 4x^2-12x+5=0 are x= 5/2 ,x= 1/2

Find the zeros of 4x^2-12x+5=0

The zeros of 4x^2-12x+5=0 are x= 5/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 12 x + 5 = 0

x = \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = 2.5, x = 0.5

Solution steps

4 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{2}

2 x^{2} + 4 = x

4 b^{2} - 21 b + 5

20 = 5 h

7 x = 1

4 m^{2} - 36 = 0

What are the solutions to the equation 4x^2-12x+5=0 ?
The solutions to the equation 4x^2-12x+5=0 are x= 5/2 ,x= 1/2
Find the zeros of 4x^2-12x+5=0
The zeros of 4x^2-12x+5=0 are x= 5/2 ,x= 1/2