What are the solutions to the equation n^2-16n-51=6 ?

The solutions to the equation n^2-16n-51=6 are n=19,n=-3

Find the zeros of n^2-16n-51=6

The zeros of n^2-16n-51=6 are n=19,n=-3

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n^{2} - 16 n - 51 = 6

n = 19, n = - 3

Solution steps

n^{2} - 16 n - 51 = 6

Move

6

to the left side

n^{2} - 16 n - 57 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 57 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 57) = 22

n_{1, 2} = \frac{- ( - 16 ) \pm 22}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 16 ) + 22}{2 \cdot 1}, n_{2} = \frac{- ( - 16 ) - 22}{2 \cdot 1}

n = \frac{- ( - 16 ) + 22}{2 \cdot 1} : 19

n = \frac{- ( - 16 ) - 22}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

n = 19, n = - 3

7 x^{2} - 3 x = 0

(4 g + 10) + (3 g - 13) > 46

1728

- 5 x + 25 > 5 (x - 5)

4410

What are the solutions to the equation n^2-16n-51=6 ?
The solutions to the equation n^2-16n-51=6 are n=19,n=-3
Find the zeros of n^2-16n-51=6
The zeros of n^2-16n-51=6 are n=19,n=-3