What is (-x^2y^4)^3(x^3y^{-1})^2 ?

The solution to (-x^2y^4)^3(x^3y^{-1})^2 is -x^{12}y^{10}

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simplify (-x^2y^4)^3(x^3y^{-1})^2

simplify

(- x^{2} y^{4})^{3} (x^{3} y^{- 1})^{2}

- x^{12} y^{10}

Solution steps

(- x^{2} y^{4})^{3} (x^{3} y^{- 1})^{2}

Simplify

(- x^{2} y^{4})^{3} : - x^{6} y^{12}

= - x^{6} y^{12} (x^{3} y^{- 1})^{2}

Simplify

(x^{3} y^{- 1})^{2} : \frac{x ^{6}}{y ^{2}}

= - x^{6} y^{12} \frac{x ^{6}}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{x ^{6} y ^{12} x ^{6}}{y ^{2}}

Simplify

\frac{y ^{12}}{y ^{2}} : y^{10}

= - x^{6} y^{10} x^{6}

Simplify

x^{6} x^{6} : x^{12}

= - x^{12} y^{10}

5 x - (x - 18) = 6 - 2 (x + 15)

\frac{10 !}{3 !}

X^{2} < 4

8 m + 8 < 9 m - 1

∣ x - 4 ∣ + 2 = 3 x + 2

What is (-x^2y^4)^3(x^3y^{-1})^2 ?
The solution to (-x^2y^4)^3(x^3y^{-1})^2 is -x^{12}y^{10}