What are the solutions to the equation x^2-2x=15 ?

The solutions to the equation x^2-2x=15 are x=5,x=-3

Find the zeros of x^2-2x=15

The zeros of x^2-2x=15 are x=5,x=-3

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x^{2} - 2 x = 15

x = 5, x = - 3

Solution steps

x^{2} - 2 x = 15

Move

15

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

3 2^{2} + 6 0^{2} = c^{2}

18 n^{4} + 25 n^{2} - 3

3 x = 2 x + 7

3 + 8 x + 2 = 37

\frac{\frac{2 π}{π}}{3}

What are the solutions to the equation x^2-2x=15 ?
The solutions to the equation x^2-2x=15 are x=5,x=-3
Find the zeros of x^2-2x=15
The zeros of x^2-2x=15 are x=5,x=-3