What are the solutions to the equation 4(x+10)^2-31=-15 ?

The solutions to the equation 4(x+10)^2-31=-15 are x=-8,x=-12

Find the zeros of 4(x+10)^2-31=-15

The zeros of 4(x+10)^2-31=-15 are x=-8,x=-12

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4 (x + 10)^{2} - 31 = - 15

x = - 8, x = - 12

Solution steps

4 (x + 10)^{2} - 31 = - 15

Move

31

to the right side

4 (x + 10)^{2} = 16

Divide both sides by

4

(x + 10)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 4 : x = - 8

Solve

x + 10 = - 4 : x = - 12

The solutions to the quadratic equation are:

x = - 8, x = - 12

- - 24

\frac{3}{x + 4} \geq 2

\frac{x}{x y}

4 x - 1 < 3

What are the solutions to the equation 4(x+10)^2-31=-15 ?
The solutions to the equation 4(x+10)^2-31=-15 are x=-8,x=-12
Find the zeros of 4(x+10)^2-31=-15
The zeros of 4(x+10)^2-31=-15 are x=-8,x=-12