What are the solutions to the equation -9x^2+12x-4=0 ?

The solutions to the equation -9x^2+12x-4=0 are x= 2/3

Find the zeros of -9x^2+12x-4=0

The zeros of -9x^2+12x-4=0 are x= 2/3

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- 9 x^{2} + 12 x - 4 = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

- 9 x^{2} + 12 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 9 ) ( - 4 )}{2 ( - 9 )}

1 2^{2} - 4 (- 9) (- 4) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 9 )}

x = \frac{- 12}{2 ( - 9 )}

\frac{- 12}{2 ( - 9 )} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

x^{5} y^{2} + x^{2} y^{5}

a^{2} - 4

lo g_{11} (11)

9 2^{2} + x^{2} = 15 2^{2}

\frac{2 n}{3} + \frac{1}{2} = \frac{3 n - 1}{6}

What are the solutions to the equation -9x^2+12x-4=0 ?
The solutions to the equation -9x^2+12x-4=0 are x= 2/3
Find the zeros of -9x^2+12x-4=0
The zeros of -9x^2+12x-4=0 are x= 2/3