What are the solutions to the equation (5x+1)(5x-2)=0 ?

The solutions to the equation (5x+1)(5x-2)=0 are x=-1/5 ,x= 2/5

Find the zeros of (5x+1)(5x-2)=0

The zeros of (5x+1)(5x-2)=0 are x=-1/5 ,x= 2/5

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(5 x + 1) (5 x - 2) = 0

x = - \frac{1}{5}, x = \frac{2}{5}

Decimal Notation

x = - 0.2, x = 0.4

Solution steps

(5 x + 1) (5 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 1 = 0 or 5 x - 2 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

5 x - 2 = 0 : x = \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = \frac{2}{5}

\frac{3 ( 8 ) ^{\frac{4}{3}}}{4}

m^{4} - 7 m^{2} n + 10 n^{2}

1 - 36 m^{2}

236 = 1.065 \cdot t + 181

∣ x - 1 ∣ = ∣ 3 x + 2 ∣

What are the solutions to the equation (5x+1)(5x-2)=0 ?
The solutions to the equation (5x+1)(5x-2)=0 are x=-1/5 ,x= 2/5
Find the zeros of (5x+1)(5x-2)=0
The zeros of (5x+1)(5x-2)=0 are x=-1/5 ,x= 2/5