What is (2x-5}{12}>\frac{-x)/4-5/3 ?

The solution to (2x-5}{12}>\frac{-x)/4-5/3 is x>-3

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(2x-5}{12}>\frac{-x)/4-5/3

\frac{2 x - 5}{12} > \frac{- x}{4} - \frac{5}{3}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

\frac{2 x - 5}{12} > \frac{- x}{4} - \frac{5}{3}

Move

\frac{- x}{4}

to the left side

\frac{5 x - 5}{12} > - \frac{5}{3}

Multiply both sides by

12

5 x - 5 > - 20

Move

5

to the right side

5 x > - 15

Divide both sides by

5

x > - 3

23 + 1 = 9

f^{- 1} (3)

(3 x - 1) = 0

\frac{6 ^{2}}{6 ^{2} - 4} - \frac{1}{6 - 2}

\frac{x - 2}{x ^{2} - 5 x + 6} \leq 1

What is (2x-5}{12}>\frac{-x)/4-5/3 ?
The solution to (2x-5}{12}>\frac{-x)/4-5/3 is x>-3