What are the solutions to the equation 3t^2-24t+45=0 ?

The solutions to the equation 3t^2-24t+45=0 are t=5,t=3

Find the zeros of 3t^2-24t+45=0

The zeros of 3t^2-24t+45=0 are t=5,t=3

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3 t^{2} - 24 t + 45 = 0

t = 5, t = 3

Solution steps

3 t^{2} - 24 t + 45 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 45}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 45 = 6

t_{1, 2} = \frac{- ( - 24 ) \pm 6}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 24 ) + 6}{2 \cdot 3}, t_{2} = \frac{- ( - 24 ) - 6}{2 \cdot 3}

t = \frac{- ( - 24 ) + 6}{2 \cdot 3} : 5

t = \frac{- ( - 24 ) - 6}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

t = 5, t = 3

- \frac{18}{15}

2 x^{3} + 9 x^{2} - 35 x \geq 0

2 x^{2} - 2 x + 13 = 0

2^{x} \cdot 2^{x}

x + 6 = x^{2}

What are the solutions to the equation 3t^2-24t+45=0 ?
The solutions to the equation 3t^2-24t+45=0 are t=5,t=3
Find the zeros of 3t^2-24t+45=0
The zeros of 3t^2-24t+45=0 are t=5,t=3